Correct. One way to solve this triangle is to use the definition of tangent to find x:

$\displaystyle\frac{{x}}{{3}}={{\tan{{65}}}}^{\circ}\approx{2.14}\Rightarrow{x}\approx{3}{\left({2.14}\right)}={6.42}\approx{6.4}\usepackage{cmbright}\Huge\$

To find y, you can either use another trigonometric function (such as cosine) or you can use the Pythagorean Theorem:

$\displaystyle{{6.4}}^{{2}}+{{3}}^{{2}}\approx{{y}}^{{2}}\Rightarrow{40.96}+{9}\approx{{y}}^{{2}}\Rightarrow{49.96}\approx{{y}}^{{2}}\Rightarrow{y}\approx{7.068}\approx{7.1}\usepackage{cmbright}\Huge\$

The two acute angles are complementary, so $\displaystyle{m}\angle{A}={{90}}^{\circ}-{{65}}^{\circ}={{25}}^{\circ}\usepackage{cmbright}\Huge\$ .