Correct. Draw $\displaystyle{{290}}^{\circ}\usepackage{cmbright}\Huge\$ in standard position. The terminal side of $\displaystyle{{290}}^{\circ}\usepackage{cmbright}\Huge\$ lies in the fourth quadrant where x is positive, so $\displaystyle{\cos{{\left({{290}}^{\circ}\right)}}}={x}\usepackage{cmbright}\Huge\$ is positive.