Incorrect. The absolute value quantity is alone, so create and solve two separate inequalities ( $\displaystyle{x}-{4}<{3}\usepackage{cmbright}\Huge\$ and $\displaystyle-{\left({x}-{4}\right)}<{3}\usepackage{cmbright}\Huge\$ ). You'll need to switch one of the inequality signs when multiplying or dividing by a negative number. What range of numbers for x makes this a true statement?