Before multiplying, reorder the numerators and cancel the common factor. $\displaystyle\frac{{{2}\cdot{5}}}{{{3}\cdot{8}}}=\frac{{{5}\cdot{2}}}{{{3}\cdot{8}}}=\frac{{{5}\cdot{1}}}{{{3}\cdot{4}}}=\frac{{5}}{{12}}\usepackage{cmbright}\Huge\$