The equation for this problem is $\displaystyle{n}\cdot{120}={48}\usepackage{cmbright}\Huge\$ . The corresponding division is $\displaystyle{48}\div{120}\usepackage{cmbright}\Huge\$ , so $\displaystyle{n}={.4}\usepackage{cmbright}\Huge\$ . Rewriting this decimal as a percent gives the answer.