This is equivalent to the original expression, but it is not in simplest form. Rewrite $\displaystyle{{c}}^{{16}}\usepackage{cmbright}\Huge\$ as $\displaystyle{{c}}^{{15}}\cdot{c}={{\left({{c}}^{{5}}\right)}}^{{3}}\cdot{c}\usepackage{cmbright}\Huge\$ . Then split the expression into a product of radicals and simplify.