The graph of $\displaystyle{y}={\sin{{\left(\theta+\frac{\pi}{{2}}\right)}}}\usepackage{cmbright}\Huge\$ is the same as the graph of $\displaystyle{y}={\sin{\theta}}\usepackage{cmbright}\Huge\$ shifted by $\displaystyle\frac{\pi}{{2}}\usepackage{cmbright}\Huge\$ units to the left. This will result in a repeating valley and hill pattern, with a hill having the y-axis running through it. This matches the given graph.