The equation for this problem is $\displaystyle{n}\cdot{180}={72}\usepackage{cmbright}\Huge\$ . The corresponding division is $\displaystyle{72}\div{180}\usepackage{cmbright}\Huge\$ , so $\displaystyle{n}={.4}\usepackage{cmbright}\Huge\$ .Rewriting this decimal as a percent gives the answer.