The second equation can be rewritten as $\displaystyle{y}=-{x}+{2}\usepackage{cmbright}\Huge\$ . These two equations are shown in the graph. Their point of intersection is $\displaystyle{\left(-{3},{5}\right)}\usepackage{cmbright}\Huge\$ . This is the solution to the system because the values $\displaystyle{x}=-{3}\usepackage{cmbright}\Huge\$ and $\displaystyle{y}={5}\usepackage{cmbright}\Huge\$ make both equations true: $\displaystyle{5}=-{3}+{8}\usepackage{cmbright}\Huge\$ and $\displaystyle-{3}+{5}={2}\usepackage{cmbright}\Huge\$ .