Substitute $\displaystyle-{2}\usepackage{cmbright}\Huge\$ for x and 2 for y in each equation.

$\displaystyle{2}-{\left(-{2}\right)}=-{4}\usepackage{cmbright}\Huge\$ $\displaystyle-{3}{\left(-{2}\right)}-{2}{\left({2}\right)}=-{10}\usepackage{cmbright}\Huge\$

$\displaystyle{4}=-{4}\usepackage{cmbright}\Huge\$ False
$\displaystyle{6}-{4}=-{10}\usepackage{cmbright}\Huge\$

$\displaystyle{2}=-{10}\usepackage{cmbright}\Huge\$ False

Since the ordered pair does not make both equations true, it is not a solution to the system.

$\displaystyle{2}-{\left(-{2}\right)}=-{4}\usepackage{cmbright}\Huge\$	$\displaystyle-{3}{\left(-{2}\right)}-{2}{\left({2}\right)}=-{10}\usepackage{cmbright}\Huge\$
$\displaystyle{4}=-{4}\usepackage{cmbright}\Huge\$ False	$\displaystyle{6}-{4}=-{10}\usepackage{cmbright}\Huge\$
	$\displaystyle{2}=-{10}\usepackage{cmbright}\Huge\$ False