You may have miscalculated the discriminant $\displaystyle{{b}}^{{2}}-{4}{a}{c}\usepackage{cmbright}\Huge\$ , got the value 0, and thought that this meant that there are 0 solutions. A quadratic equation always has either real or complex solutions. The solutions are given by the formula:

$\displaystyle{x}=\frac{{-{b}\pm\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$