You may not have noticed that the coefficient of this quadratic function is positive, although it has the same vertex as in the graph (0, 1). The graph of $\displaystyle{f{{\left({x}\right)}}}=\frac{{1}}{{2}}{{x}}^{{2}}+{1}\usepackage{cmbright}\Huge\$ would open up because of the coefficient $\displaystyle\frac{{1}}{{2}}\usepackage{cmbright}\Huge\$ , not down like the given graph.