Use the quotient property on the left side: $\displaystyle{\log{{16}}}{x}-{\log{{2}}}={\log{{\left(\frac{{{16}{x}}}{{2}}\right)}}}={\log{{8}}}{x}\usepackage{cmbright}\Huge\$

The equation becomes $\displaystyle{\log{{8}}}{x}={\log{{32}}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{8}{x}={32}.\usepackage{cmbright}\Huge\$

Divide both sides by 8: $\displaystyle{x}={4}\usepackage{cmbright}\Huge\$