This function has the same amplitude and period as the graphed function. However, its graph does not pass through the point $\displaystyle{\left(\frac{\pi}{{10}},{3}\right)}\usepackage{cmbright}\Huge\$ . When $\displaystyle{x}=\frac{\pi}{{10}}\usepackage{cmbright}\Huge\$ , $\displaystyle{y}=-{3}{\sin{{\left({5}\cdot\frac{\pi}{{10}}\right)}}}=-{3}{\sin{{\left(\frac{\pi}{{2}}\right)}}}=-{3}\cdot{1}=-{3}\usepackage{cmbright}\Huge\$ , not $\displaystyle{3}\usepackage{cmbright}\Huge\$ .