Correct. Point D (-6, 0) is the solution because when plugged into both inequalities, they result in true statements:

$\displaystyle{\left({0}\right)}\ge\frac{{1}}{{2}}{\left(-{6}\right)}+{3}\usepackage{cmbright}\Huge\$

$\displaystyle{\left({0}\right)}<{2}\usepackage{cmbright}\Huge\$