Incorrect. Remember that $\displaystyle{{n}}^{{-{{a}}}}=\frac{{1}}{{{n}}^{{a}}}={{\left(\frac{{1}}{{n}}\right)}}^{{a}}\usepackage{cmbright}\Huge\$ . How does this help you simplify $\displaystyle{{\left(\frac{{1}}{{2}}\right)}}^{{-{{6}}}}\usepackage{cmbright}\Huge\$ ?