Incorrect. Remember that $\displaystyle{{3}}^{{x}}{{3}}^{{y}}={{3}}^{{{x}+{y}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{{\left({{3}}^{{a}}\right)}}^{{b}}={{3}}^{{{a}{b}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{{3}}^{{-{{a}}}}=\frac{{1}}{{{3}}^{{a}}}\usepackage{cmbright}\Huge\$ . The expression can be written like this: $\displaystyle\frac{{{{\left({{3}}^{{2}}{{3}}^{{7}}\right)}}^{{3}}}}{{{{3}}^{{-{{3}}}}{{3}}^{{5}}}}=\frac{{{\left({{3}}^{{{2}+{7}}}\right)}}^{{3}}}{{{{3}}^{{-{3}+{5}}}}}\usepackage{cmbright}\Huge\$ . What steps do you have to do now to solve this problem?