Correct. The quotient equals $\displaystyle{1.25}\div{2.5}\cdot{\left({{10}}^{{7}}\div{{10}}^{{12}}\right)}\usepackage{cmbright}\Huge\$ , which equals $\displaystyle{0.5}\cdot{{10}}^{{{7}-{12}}}={0.5}\cdot{{10}}^{{-{{5}}}}\usepackage{cmbright}\Huge\$ . Since there is not one digit (from 1 to 9) to the left of the decimal point, we need to convert to get $\displaystyle{\left({5}\cdot{{10}}^{{-{{1}}}}\right)}\cdot{{10}}^{{-{{5}}}}={5}\cdot{{10}}^{{-{{6}}}}\usepackage{cmbright}\Huge\$ .