Incorrect. In this case, $\displaystyle\frac{{{{\left({{a}}^{{-{{3}}}}{{b}}^{{2}}{{c}}^{{-{{4}}}}\right)}}^{{3}}}}{{{\left({{a}}^{{-{{4}}}}{b}{{c}}^{{2}}\right)}}^{{4}}}\usepackage{cmbright}\Huge\$ can be simplified to $\displaystyle\frac{{{{a}}^{{-{3}{\left({3}\right)}}}{{b}}^{{{2}{\left({3}\right)}}}{{c}}^{{-{4}{\left({3}\right)}}}}}{{{{a}}^{{-{4}{\left({4}\right)}}}{{b}}^{{4}}{{c}}^{{{2}{\left({4}\right)}}}}}\usepackage{cmbright}\Huge\$ , which can then be simplified to $\displaystyle\frac{{{{a}}^{{-{{9}}}}{{b}}^{{6}}{{c}}^{{-{{12}}}}}}{{{{a}}^{{-{{16}}}}{{b}}^{{4}}{{c}}^{{8}}}}\usepackage{cmbright}\Huge\$ . Remember that $\displaystyle\frac{{{{x}}^{{n}}}}{{{{x}}^{{m}}}}={{x}}^{{{n}-{m}}}\usepackage{cmbright}\Huge\$ . Does this help you simplify the expression?