Correct. Applying the rules of exponents, you find that this expression simplifies to $\displaystyle{{b}}^{{-{{16}}}}{{c}}^{{2}}\usepackage{cmbright}\Huge\$ . Since $\displaystyle{{a}}^{{{8}-{\left({8}\right)}}}={{a}}^{{0}}={1}\usepackage{cmbright}\Huge\$ , we can leave this out of the simplified expression.