Correct. Simplify the expression $\displaystyle{{\left({{x}}^{{-{{2}}}}{{y}}^{{4}}\right)}}^{{-{{3}}}}\usepackage{cmbright}\Huge\$ first, then multiply it by $\displaystyle{{x}}^{{2}}{{y}}^{{-{{4}}}}\usepackage{cmbright}\Huge\$ , and then square that entire quantity. It simplifies to $\displaystyle{{x}}^{{16}}{{y}}^{{-{{32}}}}\usepackage{cmbright}\Huge\$ .