Fill in the powers of a, b and c to make the equation true.

$\displaystyle\frac{{{\left({{a}}^{{10}}{{b}}^{{9}}\right)}}^{{3}}}{{{\left({{a}}^{{8}}{{b}}^{{4}}{{c}}^{{-{{2}}}}\right)}}^{{3}}}={{a}}^{?}{{b}}^{?}{{c}}^{?}\usepackage{cmbright}\Huge\$

Exponents may be positive, negative, or 0.