Correct. Identifying the squares in the expression, you find: $\displaystyle\sqrt{{{600}{{a}}^{{9}}{{b}}^{{7}}{{c}}^{{11}}}}=\sqrt{{{6}\cdot{{10}}^{{2}}\cdot{{\left({{a}}^{{4}}\right)}}^{{2}}\cdot{a}\cdot{{\left({{b}}^{{3}}\right)}}^{{2}}\cdot{b}\cdot{{\left({{c}}^{{5}}\right)}}^{{2}}\cdot{c}}}\usepackage{cmbright}\Huge\$ . Pulling out the squares results in the expression $\displaystyle{10}{{a}}^{{4}}{{b}}^{{3}}{{c}}^{{5}}\sqrt{{{6}{a}{b}{c}}}\usepackage{cmbright}\Huge\$ .