Pulling out cubed terms, you find that: $\displaystyle{\sqrt[{{3}}]{{{144}{{x}}^{{17}}}}}={\sqrt[{{3}}]{{{{2}}^{{3}}\cdot{2}\cdot{3}\cdot{3}\cdot{{\left({{x}}^{{5}}\right)}}^{{3}}\cdot{{x}}^{{2}}}}}={2}{{x}}^{{5}}{\sqrt[{{3}}]{{{18}{{x}}^{{2}}}}}\usepackage{cmbright}\Huge\$