Identifying the fifth roots under the radical, you find: $\displaystyle{\sqrt[{{5}}]{{{160}{{a}}^{{11}}{{b}}^{{43}}{{c}}^{{17}}}}}={\sqrt[{{5}}]{{{{2}}^{{5}}\cdot{5}\cdot{{\left({{a}}^{{2}}\right)}}^{{5}}\cdot{a}\cdot{{\left({{b}}^{{8}}\right)}}^{{5}}\cdot{{b}}^{{3}}\cdot{{\left({{c}}^{{3}}\right)}}^{{5}}\cdot{{c}}^{{2}}}}}\usepackage{cmbright}\Huge\$ . This simplifies to $\displaystyle{2}{{a}}^{{2}}{{b}}^{{8}}{{c}}^{{3}}{\sqrt[{{5}}]{{{5}{a}{{b}}^{{3}}{{c}}^{{2}}}}}\usepackage{cmbright}\Huge\$ .