Correct. Given $\displaystyle{a}={6}\usepackage{cmbright}\Huge\$ and $\displaystyle{b}={8}\usepackage{cmbright}\Huge\$ , the Pythagorean Theorem gives us $\displaystyle{{c}}^{{2}}={{a}}^{{2}}+{{b}}^{{2}}={{6}}^{{2}}+{{8}}^{{2}}={36}+{64}={100}\usepackage{cmbright}\Huge\$ , so $\displaystyle{c}=\sqrt{{{100}}}={10}\usepackage{cmbright}\Huge\$ .