Correct. If $\displaystyle{\sqrt[{{3}}]{{{2}{x}-{1}}}}={5}\usepackage{cmbright}\Huge\$ , then $\displaystyle{{\left({\sqrt[{{3}}]{{{2}{x}-{1}}}}\right)}}^{{3}}={{5}}^{{3}}={125}\usepackage{cmbright}\Huge\$ , so $\displaystyle{2}{x}-{1}={125}\usepackage{cmbright}\Huge\$ . Then, $\displaystyle{2}{x}={126}\usepackage{cmbright}\Huge\$ , so $\displaystyle{x}={63}\usepackage{cmbright}\Huge\$ .