Incorrect. If $\displaystyle{\sqrt[{{3}}]{{{x}}}}+{1}={5}{\sqrt[{{3}}]{{{x}}}}\usepackage{cmbright}\Huge\$ , then $\displaystyle{1}={4}{\sqrt[{{3}}]{{{x}}}}\usepackage{cmbright}\Huge\$ . Continue to simplify to get an equation of the form $\displaystyle{\sqrt[{{3}}]{{{x}}}}\usepackage{cmbright}\Huge\$ = a number, then cube both sides of the equation to get rid of the radical.