Correct. $\displaystyle{\left({x}+{2}\right)}{\left({{x}}^{{2}}+{x}-{10}\right)}={{x}}^{{3}}+{{x}}^{{2}}-{10}{x}+{2}{{x}}^{{2}}+{2}{x}-{20}\usepackage{cmbright}\Huge\$ . Combining like terms yields the answer of $\displaystyle{{x}}^{{3}}+{3}{{x}}^{{2}}-{8}{x}-{20}\usepackage{cmbright}\Huge\$ .