Correct. You successfully multiplied the two terms. $\displaystyle{{\left({3}{{x}}^{{5}}{y}\right)}}^{{2}}{\left({2}{x}\right)}={\left({3}{{x}}^{{5}}{y}\right)}{\left({3}{{x}}^{{5}}{y}\right)}{\left({2}{x}\right)}={18}{{x}}^{{11}}{{y}}^{{2}}\usepackage{cmbright}\Huge\$ .