Correct. You successfully multiplied the two terms. $\displaystyle{{\left(-{5}{{x}}^{{3}}{y}\right)}}^{{2}}{\left(\frac{{3}}{{5}}{{x}}^{{2}}\right)}={\left(-{5}{{x}}^{{3}}{y}\right)}{\left(-{5}{{x}}^{{3}}{y}\right)}{\left(\frac{{3}}{{5}}{{x}}^{{2}}\right)}={\left(\frac{{3}}{{5}}{{x}}^{{2}}\right)}\usepackage{cmbright}\Huge\$ .