Correct. You successfully multiplied the two terms. $\displaystyle{4}{{x}}^{{17}}{{y}}^{{9}}\usepackage{cmbright}\Huge\$ is the product of the simplified terms $\displaystyle{64}{{x}}^{{15}}{{y}}^{{3}}\usepackage{cmbright}\Huge\$ and $\displaystyle\frac{{1}}{{16}}{{x}}^{{2}}{{y}}^{{6}}\usepackage{cmbright}\Huge\$ .