An artist creates an ice sculpture in the form of a solid cone, and then hollows out a smaller, inverted cone inside. The large cone has a radius of $\displaystyle{10}{x}\usepackage{cmbright}\Huge\$ inches and a height of $\displaystyle{25}{x}\usepackage{cmbright}\Huge\$ inches, while the smaller cone has a radius of $\displaystyle{4}{x}\usepackage{cmbright}\Huge\$ inches and a height of $\displaystyle{10}{x}\usepackage{cmbright}\Huge\$ inches. Given that the formula for the volume of the cone is $\displaystyle\frac{{1}}{{3}}\pi{{r}}^{{2}}{h}\usepackage{cmbright}\Huge\$ , where r = radius and h = height, what is the amount of solid ice in the sculpture?