Incorrect. Recognize that $\displaystyle{{\left({4}{{x}}^{{2}}-{15}\right)}}^{{2}}\usepackage{cmbright}\Huge\$ has a special product, since it is the square of a difference. Use the formula $\displaystyle{{\left({a}-{b}\right)}}^{{2}}={{a}}^{{2}}-{2}{a}{b}+{{b}}^{{2}}\usepackage{cmbright}\Huge\$ to find the first term. (And remember the rules of exponents: $\displaystyle{{\left({a}{b}\right)}}^{{2}}={{a}}^{{2}}{{b}}^{{2}}\usepackage{cmbright}\Huge\$ .)