Simplify:

$\displaystyle{\left({120}{{a}}^{{3}}-{32}{{a}}^{{2}}+{7}{a}\right)}-{\left({10}{{a}}^{{3}}-{16}{{a}}^{{2}}-{4}\right)}={110}{{a}}^{{3}}\usepackage{cmbright}\Huge\$ _________ $\displaystyle+{7}{a}+{4}\usepackage{cmbright}\Huge\$

Fill in the blank with the missing term. To represent the exponent ab, write a^b.