Incorrect. Remember that $\displaystyle{{\left({x}-{3}\right)}}^{{2}}\usepackage{cmbright}\Huge\$ is equal to $\displaystyle{\left({x}-{3}\right)}{\left({x}-{3}\right)}\usepackage{cmbright}\Huge\$ . This can be rewritten as $\displaystyle{x}{\left({x}-{3}\right)}-{3}{\left({x}-{3}\right)}\usepackage{cmbright}\Huge\$ . From here, you can distribute the terms outside each parentheses and simplify. Does that help you solve the problem?