Incorrect. You can use the distributive property (in reverse) to write $\displaystyle{{x}}^{{2}}+{3}{x}\usepackage{cmbright}\Huge\$ as $\displaystyle{x}{\left({x}+{3}\right)}\usepackage{cmbright}\Huge\$ and to write $\displaystyle{2}{x}+{6}\usepackage{cmbright}\Huge\$ as $\displaystyle{2}{\left({x}+{3}\right)}\usepackage{cmbright}\Huge\$ . This gives $\displaystyle{x}{\left({x}+{3}\right)}+{2}{\left({x}+{3}\right)}\usepackage{cmbright}\Huge\$ . Can you use the distributive property again to find the missing factor?