Correct. Notice that a squared binomial, such as $\displaystyle{\left({x}+{9}\right)}{\left({x}+{9}\right)}\usepackage{cmbright}\Huge\$ , results in a three-term polynomial: in this case, $\displaystyle{{x}}^{{2}}+{18}{x}+{81}\usepackage{cmbright}\Huge\$ . When the signs are different but the constants are the same for each binomial, as in $\displaystyle{\left({x}+{9}\right)}{\left({x}-{9}\right)}\usepackage{cmbright}\Huge\$ , the result is a two-term polynomial: in this case, $\displaystyle{{x}}^{{2}}-{81}\usepackage{cmbright}\Huge\$ .