This graph does indeed represent $\displaystyle{y}=\frac{{1}}{{10}}{{x}}^{{2}}\usepackage{cmbright}\Huge\$ . The small coefficient causes the curve to be more gradual than in $\displaystyle{y}={{x}}^{{2}}\usepackage{cmbright}\Huge\$ . Since there is no c term, the vertex of the parabola will rest on the origin of the graph.