This graph does represent $\displaystyle{y}=-{2}{{x}}^{{2}}\usepackage{cmbright}\Huge\$ . Substituting $\displaystyle{x}={1}\usepackage{cmbright}\Huge\$ into the equation, you find that $\displaystyle{y}=-{2}{{\left({1}\right)}}^{{2}}=-{2}\usepackage{cmbright}\Huge\$ , and the point $\displaystyle{\left({1},-{2}\right)}\usepackage{cmbright}\Huge\$ rests on the graph.