Correct. The intercept form of the equation is $\displaystyle{y}={{\left({x}+{1}\right)}}^{{2}}\usepackage{cmbright}\Huge\$ . As a result, $\displaystyle{x}=-{1}\usepackage{cmbright}\Huge\$ when $\displaystyle{y}={0}\usepackage{cmbright}\Huge\$ , so the root of the equation is $\displaystyle{\left(-{1},{0}\right)}\usepackage{cmbright}\Huge\$ .