Correct. The intercept form of the equation is $\displaystyle{y}=-{1}{{\left({2}{x}+{1}\right)}}^{{2}}\usepackage{cmbright}\Huge\$ . As a result, $\displaystyle{x}=-\frac{{1}}{{2}}\usepackage{cmbright}\Huge\$ when $\displaystyle{y}={0}\usepackage{cmbright}\Huge\$ , so the root is $\displaystyle{\left(-\frac{{1}}{{2}},{0}\right)}\usepackage{cmbright}\Huge\$ .