Incorrect. If the polynomial can be factored, the factorization will "look like" $\displaystyle{3}{{x}}^{{2}}+{4}{x}+{1}={\left({3}{x}+{r}\right)}{\left({x}+{s}\right)}\usepackage{cmbright}\Huge\$ . Can you find values for r and s so that $\displaystyle{r}+{3}{s}={4}\usepackage{cmbright}\Huge\$ and $\displaystyle{r}{s}={1}\usepackage{cmbright}\Huge\$ ?