Incorrect. If the polynomial can be factored, the factorization will "look like" $\displaystyle{3}{{x}}^{{2}}+{5}{x}+{2}={\left({3}{x}+{r}\right)}{\left({x}+{s}\right)}\usepackage{cmbright}\Huge\$ (since the coefficient of $\displaystyle{{x}}^{{2}}\usepackage{cmbright}\Huge\$ is 3). Are there integers r and s so that $\displaystyle{r}{s}={2}\usepackage{cmbright}\Huge\$ and $\displaystyle{r}+{3}{s}={5}\usepackage{cmbright}\Huge\$ ?