Incorrect. Notice that you can factor out the 3 so that $\displaystyle{y}={3}{\left({{x}}^{{2}}-{2}{x}\right)}\usepackage{cmbright}\Huge\$ . Now, add c to the right and 3c to the left so that $\displaystyle{y}+{3}{c}={3}{\left({{x}}^{{2}}-{2}{x}+{c}\right)}\usepackage{cmbright}\Huge\$ . What value for c makes $\displaystyle{{x}}^{{2}}-{2}{x}+{c}\usepackage{cmbright}\Huge\$ a perfect square trinomial? Find c, write the completed square as a binomial squared, and then solve for y.