Correct. $\displaystyle{y}={2}{{x}}^{{2}}-{12}{x}+{20}={2}{\left({{x}}^{{2}}-{6}{x}\right)}+{20}\usepackage{cmbright}\Huge\$ . Completing the square, you found $\displaystyle{y}+{2}{\left({9}\right)}={2}{\left({{x}}^{{2}}-{6}{x}+{9}\right)}+{20}\usepackage{cmbright}\Huge\$ . Factoring the trinomial, this can be rewritten $\displaystyle{y}={2}{{\left({x}-{3}\right)}}^{{2}}+{2}\usepackage{cmbright}\Huge\$ . Note that the coordinates for the vertex would be (3, 2).