Correct. $\displaystyle{y}={20}{{x}}^{{2}}-{40}{x}+{12}={20}{\left({{x}}^{{2}}-{2}{x}\right)}+{12}\usepackage{cmbright}\Huge\$ . Completing the square, you found $\displaystyle{y}+{20}{\left({1}\right)}={20}{\left({{x}}^{{2}}-{2}{x}+{1}\right)}+{12}\usepackage{cmbright}\Huge\$ . Factoring the trinomial, this can be rewritten $\displaystyle{y}={20}{{\left({x}-{1}\right)}}^{{2}}-{8}\usepackage{cmbright}\Huge\$ . Note that the coordinates for the vertex would be (1, -8).