Incorrect. Factor out the 4 so that $\displaystyle{y}={4}{\left({{x}}^{{2}}-{8}{x}\right)}+{30}\usepackage{cmbright}\Huge\$ . Now complete the square by adding c to the right and 4c to the left so that $\displaystyle{y}+{4}{c}={12}{\left({{x}}^{{2}}-{8}{x}+{c}\right)}\usepackage{cmbright}\Huge\$ . What value for c makes $\displaystyle{{x}}^{{2}}-{8}{x}+{c}\usepackage{cmbright}\Huge\$ a perfect square trinomial? Make sure your final equation is in vertex form, $\displaystyle{y}={a}{{\left({x}-{h}\right)}}^{{2}}+{k}\usepackage{cmbright}\Huge\$ .