Incorrect. Notice that the coefficient of $\displaystyle{{x}}^{{2}}{\left({4}={{2}}^{{2}}\right)}\usepackage{cmbright}\Huge\$ and the constant term $\displaystyle{\left({1}={{1}}^{{2}}={{\left(-{1}\right)}}^{{2}}\right)}\usepackage{cmbright}\Huge\$ are both squares. Can this polynomial be factored as the square of a binomial?