$\displaystyle{\left({2}{x}+{3}\right)}{\left({2}{x}-{3}\right)}={4}{{x}}^{{2}}-{9}\usepackage{cmbright}\Huge\$ (the difference of two squares), so this answer is incorrect. Is $\displaystyle{4}{{x}}^{{2}}+{12}{x}+{9}\usepackage{cmbright}\Huge\$ a perfect square trinomial?